Question
Evaluate.$$\sin ^{-1}\left(\sin \frac{2 \pi}{3}\right)$$
Step 1
This is because the inverse sine function, $\sin^{-1}(x)$, is defined only for the interval $[-1,1]$ and its range is $[-\frac{\pi}{2}, \frac{\pi}{2}]$. Show more…
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