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Problem 59 Hard Difficulty

Evaluate the definite integral.

$ \displaystyle \int^2_1 \frac{e^{1/x}}{x^2} \, dx $

Answer

$$e-\sqrt{e}$$

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Video Transcript

given our problem, we know that Are you convene? Seen as one of X which means our d axe once we take the derivative is negative Xcor d'you Which means now we know that we have negative times the intro from one to dio of either you do you now recall of the integral eat of the U is actually simply eat of the U and our upper bound is now going to be 1/2 because we know are a is gonna be 1/2 and r b is one over once or B is considered to be one So ensure that you remember to do the crypt bounds And now you consider attitude on we end up with even a square root of e.