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Evaluate the definite integral.
$ \displaystyle \int^3_0 \frac{dx}{5x + 1} $
$\frac{4 \ln 2}{5}$
01:18
Frank L.
Calculus 1 / AB
Chapter 5
Integrals
Section 5
The Substitution Rule
Integration
Oregon State University
Harvey Mudd College
Idaho State University
Boston College
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from the problem we've been given, the first thing you can do is pull out the constant 1/5. Then we can rewrite the integral. Now we know as we established that you is five. Expose one rate. It's the denominator. Therefore, do you is simply five d backs. Therefore now the limits of integration change from five times 05 times three plus one on the top, which is 16 and five time zero post went on the bottom, which is simply one. So the constant remains on the outside as we just established our limits or from our bouncer from 1 to 16. Take the integral and we end up with four natural log with two divided by five.
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