Problem

Evaluate the definite integral. $ \displaysty…

01:12

Problem 69 Hard Difficulty

Evaluate the definite integral.

$ \displaystyle \int^{e^4}_{e} \frac{dx}{x \sqrt{\ln x}} $

Answer

$2$

Discussion

You must be signed in to discuss.

Top Calculus 1 / AB Educators

Watch More Solved Questions in Chapter 5

Problem 1

Problem 2

Problem 3

Problem 4

Problem 5

Problem 6

Problem 7

Problem 8

Problem 9

Problem 10

Problem 11

Problem 12

Problem 13

Problem 14

Problem 15

Problem 16

Problem 17

Problem 18

Problem 19

Problem 20

Problem 21

Problem 22

Problem 23

Problem 24

Problem 25

Problem 26

Problem 27

Problem 28

Problem 29

Problem 30

Problem 31

Problem 32

Problem 33

Problem 34

Problem 35

Problem 36

Problem 37

Problem 38

Problem 39

Problem 40

Problem 41

Problem 42

Problem 43

Problem 44

Problem 45

Problem 46

Problem 47

Problem 48

Problem 49

Problem 50

Problem 51

Problem 52

Problem 53

Problem 54

Problem 55

Problem 56

Problem 57

Problem 58

Problem 59

Problem 60

Problem 61

Problem 62

Problem 63

Problem 64

Problem 65

Problem 66

Problem 67

Problem 68

Problem 69

Problem 70

Problem 71

Problem 72

Problem 73

Problem 74

Problem 75

Problem 76

Problem 77

Problem 78

Problem 79

Problem 80

Problem 81

Problem 82

Problem 83

Problem 84

Problem 85

Problem 86

Problem 87

Problem 88

Problem 89

Problem 90

Problem 91

Problem 92

Problem 93

Problem 94

Video Transcript

we can consider Are you to be natural of acts, Which means that our d axe is simply axe d'you. Okay, this now means that our limits of integration change. Our bottom limit is gonna be natural. Lot of E, which is simply one in our top limit, is gonna be natural lot of each of the fourth, which is simply for because remember, Ellen, times e just has one. It just cancels out, Okay, Now we're gonna be using the power will, which means we increased the exported by one. And then we divide by the new expert. So from negative 1/2 which is the same thing as one over scored of you, the expensive 1/2 we add one and we end up with positive 1/2 defined by the exponents. Now, using the fundamental dear. My calculus, we can pull again. We end up with two

Amrita B.

Topics

Integrals

Integration

Calculus: Early Transcendentals

Chapter 5

Integrals

Section 5

The Substitution Rule

Problem