Question
Evaluate the definite integral.$$\int_{0}^{1} \frac{x^{3}-1}{x^{2}-4} d x$$
Step 1
Step 1: First, we can simplify the given integral by dividing the numerator and the denominator by $x^{2}$, which gives us: $$ \int_{0}^{1} \frac{x^{3}-1}{x^{2}-4} d x = \int_{0}^{1} \frac{x-1/x}{1-4/x^{2}} d x $$ Show more…
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