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Evaluate the definite integral.$\int_{0}^{1} \sqrt[3]{1+7 x} d x$
$\frac{51}{28}$
Calculus 1 / AB
Calculus 2 / BC
Chapter 5
Integrals
Section 4
The Substitution Rule
Integration Techniques
Baylor University
Idaho State University
Boston College
Lectures
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this question asks us to evaluate the given into girl We know that. Are you congee one plus seven x Therefore, we know that 1/7 sti you can be equivalent to D backs. Therefore, when writing are integral, we know we can pull out the 1/7. You know, we could change the limits of integration if X is one, then you is eight if x zero than you is one. And then when integrating, we can increase the exponents by one divide by the new exponents. This gives us 3/28 huge the 4/3 and then from 8 to 1 we're now plugging in. You have a minus. You off one. And we have 3/28 on the outside. So 3/28 times 16 minus one, which is 51/28.
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