00:01
Okay, this time we want to find the anti -derivative of a quotient, and there's no quotient rule or anything similar to that.
00:09
So we've got to figure out some way to make this into something that we know.
00:15
And the thing that i noticed is that in the denominator, you only have one term.
00:21
So we could separate this into two fractions, one over the cosine squared plus cosine squared over the cosine squared.
00:29
So that's what i'm going to do.
00:32
Again, the reason why i did that, i'm doing that, because there's only one thing on the bottom here.
00:39
Plus, it makes it work.
00:49
Okay, now one over the cosine squared is still a fraction, but it's a fraction equal to a different trig function.
00:56
It's equal to the secant squared of theta plus cosine squared over cosine squared is one.
01:08
Okay, now theta is just a variable, just like x is or y or whatever.
01:12
It doesn't matter what letter you use there.
01:15
If the theta is bothering, you change it to x.
01:19
All right.
01:21
Whose derivative is the secon squared? the secon squared is the derivative of the tangent.
01:29
So the tangent is the anti -derivative of the sequence...