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Section 3 .2, problem number 12, we're dealing with properties of determinants.
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We've got a 4 -5 -4 matrix.
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They've asked us to find determinants by using elementary row operations to reduce it to upper triangular form.
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So i'd just like to go ahead and say, okay, everything in column 1 below that 7 needs to be cleared out to be a 0.
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So the way to make this happen is negative 2 times row 1, add that to row 2.
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And let that become the new row 2.
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So when we do that operation, we have 7, negative 1, 3, 4.
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So negative 2 times 7, negative 14, add to get 0.
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Negative 2 times negative 1 is 2.
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Add that to 2 and get 4.
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Negative 2 times 3 is negative 6, add to 4, and you get negative 2.
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Negative 2 times 4 is negative 8, add to 6, and get negative 2.
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2.
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Now while i'm here, the next thing i want to clear will be that 21.
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So negative 3 row 1 plus row 3.
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That will become my new row 3.
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So negative 3 times 7 is negative 21.
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I had to get 0.
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Negative 3 times negative 1 is 3.
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3 plus 1 is 4.
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Negative 3 times 3 is negative 9 negative 9 plus 3 is negative 6 negative 3 times 4 is negative 12 negative 12 positive 4 is negative 8 and then the last thing i want to clear would be this negative 7 you can do that by adding row 1 to row 4 and letting that become the new row 4 so 7 plus negative 7 negative 4 plus 1 5 plus 1 5 plus 3 and 8 plus 4.
02:15
So now i've cleared everything in that first column beneath the diagonal, and now i just simply need to go forward and to clear everything below the 4, that first 4, in the second diagonal.
02:27
So let's just go ahead and break this into steps.
02:31
So i want to clear this 4 right here.
02:33
So that operation is going to be negative row 2 plus row 3 and let that become the new row 3...