00:01
This question gives us a 3x3 matrix and asks us to find the determinant.
00:06
The matrix that it gives, which we'll call a, looks like this.
00:10
Negative 5, 49, 1, 0, negative 2, and 0, negative 5, 7.
00:19
So as always, when we find the determinant of 3x3 matrices, i'm going to choose a row or column and find the corresponding cofactors and scale them by the elements in that row or column, and then add them all together.
00:32
I'll write it out so you'll see what i mean more clearly.
00:34
I'm going to choose this row here, row number two, because it has a zero, which we know we like, because it will cancel out co -factors, and it has other small numbers that are easy to work with.
00:48
So the determinant of a is going to look like this.
00:52
It's going to be element 2 -1, which we know is 1, times co -factor 2 -1, plus element 2 -2, which of course is 0 times co -factor 2 -2, plus element 2 3, which is negative 2, times co -factor 2 3.
01:10
Now, right away, we know that this term cancels out because 0 times anything is just 0.
01:16
So we're left with only two co -factors that we need to find.
01:19
I'm going to find each one individually, then we'll add them all together.
01:23
So the first, i'm finding 1 times co -factor 2 -1, which is just equal to the co -factor 2 -1.
01:30
And we know co -factor 2 -1 is the same thing as negative 1 to the 2 plus 1.
01:37
Times the determinant of minor to 1.
01:41
Now what's minor to 1? remember, minors are, if we take the entire matrix and then omit the column and row that are specified.
01:49
So here, minor 21, we're going to omit column 2 and row 1.
01:55
And we're left with 4, 9, negative 5, 7.
01:58
So let me write that in.
01:59
We'll have negative 1 to the 3rd times the determinant of 4, 9, negative 5, and 7.
02:09
Of course, negative 1 to the 3rd, negative 1 to any odd number is going to be negative 1.
02:13
So we'll have negative 1.
02:14
And when we find the determinant of 2 by 2 matrices, but now you're a pro at this, remember we take the diagonal, the product of the diagonal, and then subtract from that the product of the antidiagonal.
02:24
So we'll have 4 times 7, which of course is 28, and then subtract negative 5 times 9, which is negative 45...