Question
Evaluate the expression.$$\left[\left(-\frac{1}{3}\right)^{2}\right]^{-3}$$
Step 1
$$\left(-\frac{1}{3}\right)^{2}$$ To square a fraction, we square the numerator and the denominator separately. $$\left(-\frac{1}{3}\right)^{2} = \left(\frac{(-1)^{2}}{3^{2}}\right) = \frac{1}{9}$$ Show more…
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