$$\left(\frac{1}{8}\right)^{1 / 3}$$
To simplify this, we can rewrite $\frac{1}{8}$ as $2^{-3}$.
$$\left(2^{-3}\right)^{1 / 3}$$
Using the property of exponents, we can multiply the exponents.
$$2^{-3 \cdot \frac{1}{3}}$$
Simplifying the exponent gives
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