00:01
Section 7 .1, problem 34, we're dealing with an introduction to techniques of integration here.
00:07
So typically when you see a quadratic in three terms like this, the key is going to be completing the square.
00:14
So let's look at this x squared plus 4x plus 8.
00:20
In order to complete the square, what is half of four? that's two, you square that you get four.
00:27
So i could write it like this.
00:29
But more importantly, that gives me x plus 2.
00:32
Squared plus 4 so let's work on just the indefinite integral first so the indefinite integral of x over it's going to be written as x plus 2 squared plus 4 dx so substitution would be let u equal x plus 2 then d u is just going to be d x and we we also know that x is going to be u minus 2.
01:11
So this integral turns into replace x with u minus 2 and then you're going to have u squared plus 4 du.
01:26
So how do i work on this? let's break this into two separate integrals.
01:30
So i could say this is the integral of u over u squared plus 4 d u and then minus 2.
01:40
The integral of 1 over u squared plus 4 d u so on the left -hand side let's make a substitution that if z is equal to u squared plus 4 then d z is equal to 2 u d u d u and so to transform this if i had a 2 in front and a one -half then this would turn into the integral one -half, 2u -d -u, that's d -z, so this is just 1 over z, d -z, and you know that that is a natural log, so this just turns into one -half, natural log, absolute value of z, plus a constant of integration.
02:40
What is z? z is u -square plus 4, so this is 1 -half natural log, u -squared plus 4 and that's always positive so i don't need absolute value signs what is u squared plus 4 well u squared plus 4 that is this original expression that you see right here so x squared plus 4x plus 8 so this turns into one -half log x squared plus 4x plus 8 plus a constant integration so that's the anti -derivative of the first half.
03:21
And now let's look at the next one.
03:22
This one is just much simpler.
03:24
This is an arc tangent.
03:25
So minus 2.
03:26
And this is going to be 1 over 2, arc tangent of x over 2.
03:35
And so this is just minus arc tangent of, excuse me, not x but u.
03:43
Sorry about that.
03:51
So plus a constant...