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Evaluate the given definite integrals.$$\int_{2.75}^{3.25} \frac{d x}{\sqrt[3]{6 x+1}}$$

$\approx 0.18746$

Calculus 1 / AB

Chapter 25

Integration

Section 4

The Definite Integral

Integrals

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Hello Friends. We have to evaluate to given definite integral that is And they get sent off 2.75 two. Okay. Dx upon Give Rudolph six x plus one. Okay so we can write it in the years and off. Six X plus one. to the power of -1 x three of dx Limit is 2.75. 3.25. So the integration of this will be six express went to the power of minus of one by three plus one upon- of one x 3 plus one multiple with coefficient of X. The limit is 2.75. 3.25. Okay so we can write it six X plus one to the Pavlov two or 3 a bomb 2 14-6 2.75 and two. Um it is a parliament is 3.25. Yeah So this belief one upon four six x plus one to the power off To buy three limited 2.75 2 3.25. So this will be when we put the limit 16 to 3.25 Plus 1 to the power of two x 3- of 16 to 2.75 Plus 1 to the power of two by three. Yeah. 16 to 3.25 plus Fun. Well with 215 to the power two or 3- of 16 to 2.75 plus one to the power of two or three. Mhm. Yeah. Mhm Yeah. Yeah. Okay so we can solve it 71 folks To the power of two x 3. Mhm. 20.5 to the power of to buy three minus of 17.5 hour of two or three. So this will be a cost to 125 multiple with .74985. So this will be cost 2.18 746 So this is the answer. I hope you understood. Thank you.

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