Question
Evaluate the given indefinite integral by a trigonometric substitution where appropriate. You should be able to evaluate some of the integrals without a substitution.$$\int \sqrt{6 x-x^{2}} d x$$
Step 1
We rewrite $6x - x^2$ as $-(x^2 - 6x)$, which can be rewritten as $-(x^2 - 6x + 9 - 9)$, or $-(x - 3)^2 + 9$. So, the integral becomes $$ \int \sqrt{9 - (x - 3)^2} dx $$ Show more…
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