Question
Evaluate the given indefinite integral.$$\int \frac{\sin t}{\cos ^{2} t} d t$$
Step 1
We know that $\sin t = \tan t \cdot \cos t$ and $\cos^2 t = \sec^2 t$. So, we can rewrite the integral as follows: $$ \int \frac{\sin t}{\cos ^{2} t} d t = \int \tan t \cdot \sec^2 t dt $$ Show more…
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