00:02
In this problem, we are going to evaluate the given definite integral, that is integral from 2 square root 2 up to 4 over x times square root of x x square minus 4 d of x using trigonometric substitutions.
00:35
Let us to remove the radical sign, let us consider x is equal to 2 second theta.
00:45
This implies that dx will be equal to two derivative of second theta is second theta, 10 theta, d of theta.
01:04
Now we are going to change the limits of integration.
01:09
That is when x is equal to 2 times square root of 2, then we have 2 times square root of 2 is equal to 2 second theta.
01:23
This implies that second theta will be equal to square root of 2 or if second theta is equal to square root of 2 then theta will be pi by 4.
01:50
Now we are going to change the upper limit.
01:54
That is when x is equal to 4, then 4 is equal to 2 second...