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Evaluate the indefinite integral.
$ \displaystyle \int \frac{\cos (\pi/x)}{x^2} \, dx $
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01:59
Frank Lin
Calculus 1 / AB
Chapter 5
Integrals
Section 5
The Substitution Rule
Integration
Baylor University
University of Michigan - Ann Arbor
University of Nottingham
Idaho State University
Lectures
05:53
In mathematics, an indefinite integral is an integral whose integrand is not known in terms of elementary functions. An indefinite integral is usually encountered when integrating functions that are not elementary functions themselves.
40:35
In mathematics, integration is one of the two main operations of calculus, with its inverse operation, differentiation, being the other. Given a function of a real variable (often called "the integrand"), an antiderivative is a function whose derivative is the given function. The area under a real-valued function of a real variable is the integral of the function, provided it is defined on a closed interval around a given point. It is a basic result of calculus that an antiderivative always exists, and is equal to the original function evaluated at the upper limit of integration.
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we know that you is pi over acts. Which means that de you is pi over medevac square d axe, which means that negative g u over pi. There's one over X squared DX, which means we plot the constant negative one of her pie. We know the integral. Of course. I knew this sign you, which gives the solution of negative one of her pie sign a pie over acts cause
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