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# Evaluate the indefinite integral.$\displaystyle \int \frac{\sec^2 x}{\tan^2 x} \, dx$

## $\frac{-1}{\tan (x)}+c$Recall that this is the same as -cot $(x)+c$

Integrals

Integration

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we know that you is 10 of acts, which means that de you is seeking scrubbing backs, de acts. Which means we have the integral front over you squared, do you? Which gives us you to the negative one overnight, one received and then plugging in. We end up with this which is also collect a negative co changes of access e.

Integrals

Integration

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