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Numerade Educator

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Problem 23 Easy Difficulty

Evaluate the indefinite integral.

$ \displaystyle \int \sec^2 \theta \tan^3 \theta \, d\theta $

Answer

$\frac{1}{4} \tan ^{4} \theta+C$

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Video Transcript

We know that you iss tan of data which means that D'You the derivative is seeking square Beta de ST up, which means we have the integral of you Cube D'you using the power will gives us 1/4 you to the four plus c which back substituting for you We end up with 1/4 10 to the fourth of data plus C as our solution.