00:01
Okay, and this problem i'm going to have to do integration twice, integration my parts twice, or do a column integration.
00:11
I think that's what it's called.
00:13
Hey, let me do it both ways.
00:15
So stay tuned for the second part because it's easier.
00:19
Okay, so i'm going to let ubx squared.
00:22
And then dv is the sign of 2x, dx.
00:27
So du, 2x, dx, v.
00:32
I need a two, so that puts a one -half.
00:36
So, oops, minus one -half cosine 2x.
00:41
I get minus one -half, x squared, cosine 2x, minus the integral v -du, which makes plus cosine 2x, x -d -x.
00:55
All right, if you was x -squared before, then you needs to be x here.
01:02
Or if dv was the trig function, the first time it needs to be the trig function.
01:06
The second time...