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Evaluate the indefinite integral.$\int(3 x-2)^{20} d x$
$\frac{(3 x-2)^{21}}{63}+C$
Calculus 1 / AB
Calculus 2 / BC
Chapter 5
Integrals
Section 4
The Substitution Rule
Integration Techniques
Baylor University
Idaho State University
Boston College
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this question asks us to evaluate the given integral. We know that we can do this by making you three X minus two, which means our detox is 1/3 do you? Which means pulling out 1/3 because it's a constant. We have the integral of you to the 20 d'you, which is simply gonna be 1/3 you to the 21 divided by 21 plus c and then back substituting end. We know we have 1/3 three x minus two to the power of 21/21 plus c. And then if you want to make it as simple as possible, it would be three X minus 2 to 21. Then you can consult it the denominators to be 63 plus e.
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