Question
Evaluate the indicated limit, if it exists. Assume that $\lim _{x \rightarrow 0} \frac{\sin x}{x}=1$$$\lim _{x \rightarrow 0} \frac{\sqrt{x+4}-2}{x}$$
Step 1
The conjugate of $\sqrt{x+4}-2$ is $\sqrt{x+4}+2$. This gives us: $$\lim _{x \rightarrow 0} \frac{\sqrt{x+4}-2}{x} \cdot \frac{\sqrt{x+4}+2}{\sqrt{x+4}+2}$$ Show more…
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