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Evaluate the indicated limit, if it exists. Assume that $\lim _{x \rightarrow 0} \frac{\sin x}{x}=1$$$\lim _{x \rightarrow 0} \frac{2 x}{3-\sqrt{x+9}}$$

-12

Calculus 1 / AB

Chapter 1

Limits and Continuity

Section 3

Computation of Limits

Limits

Continuous Functions

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Okay, so I supported the limit. Other following a precision. So if you use textile that get in the denominator three money, Cyril, her start three months, three, Which is a quick deal. So we get the vision myself. So instead of doing that, why don't we multiply and divide by our contact base? And that's three plus the square root of expose line. Okay, so that gives us, um let's see Vore numerator as is. And that's multiply out our denominator. Okay, so that gives us three times three, which is nine minus. Um, Marnix nine. Do we see our nine councils? And once or nine cancels, we can cancel out this, um, this X as well. So we get the limits as X approaches zero of 92 times three plus the square root of x plus. Fine. Okay. And I were using drugs off. We get negative, too. Times three plus The square root of joe coastline. That's just nine. Some get negative two times. Did it for three. Which six, and that gives us negative 12

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