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Evaluate the integral.

$ \displaystyle \int e^{2 \theta} \sin 3 \theta d \theta $

$\frac{13}{4} I=\frac{1}{2} e^{2 \theta} \sin 3 \theta-\frac{3}{4} e^{2 \theta} \cos 3 \theta+C_{1} .$ Hence, $I=\frac{1}{13} e^{2 \theta}(2 \sin 3 \theta-3 \cos 3 \theta)+C,$ where $C=\frac{4}{13} C_{1}$

Integration Techniques

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Missouri State University

Harvey Mudd College

Idaho State University

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