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Problem

Evaluate the integral. $ \displaystyle \int \f…

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Problem 72 Hard Difficulty

Evaluate the integral.

$ \displaystyle \int \frac{\ln (x + 1)}{x^2}\ dx $


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Related Courses

Calculus 2 / BC

Calculus: Early Transcendentals

Chapter 7

Techniques of Integration

Section 5

Strategy for Integration

Related Topics

Integration Techniques

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Video Thumbnail

01:53

Integration Techniques - Intro

In mathematics, integration is one of the two main operations in calculus, with its inverse, differentiation, being the other. Given a function of a real variable, an antiderivative, integral, or integrand is the function's derivative, with respect to the variable of interest. The integrals of a function are the components of its antiderivative. The definite integral of a function from a to b is the area of the region in the xy-plane that lies between the graph of the function and the x-axis, above the x-axis, or below the x-axis. The indefinite integral of a function is an antiderivative of the function, and can be used to find the original function when given the derivative. The definite integral of a function is a single-valued function on a given interval. It can be computed by evaluating the definite integral of a function at every x in the domain of the function, then adding the results together.

Video Thumbnail

27:53

Basic Techniques

In mathematics, a technique is a method or formula for solving a problem. Techniques are often used in mathematics, physics, economics, and computer science.

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Problem 10
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Problem 15
Problem 16
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Problem 18
Problem 19
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Problem 49
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Problem 54
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Problem 82
Problem 83
Problem 84

Video Transcript

let's start off here with the use up and take you to be X plus one. No. So do you equals the X. And we also can write you minus one equals X. So this becomes in a girl, Ellen, You over x Claire So that you might this once Where do you So that should be a two down there in the exponents because of the square up here. Now we have a new wonder girls to work with And for this new in a grove, let's go ahead and use by parts. Let's take while amusing you already let me use w equals Alan. You dd d w equals one over you deal and then Devi will be you minus one to the minus two. So use the power rule here to integrate and you get negative one over You might this one now using the formula for my parts. In this case, it's w v rights in Abril the dw So we get negative natural log of you over you minus one and then minus and a girl and that we have V and then dw solar multiplying these together we see that there's a minus sign here. This will turn this into a plus sign. And then we just have one over you from this. You up here and then you might just want from over here to you, which is coming from here. So let me just call on coordinate those this coming from there, and then you might a swan. You mind this one? Now, we could go ahead and rewrite this instagram as a over you Beale Review minus one. That's our partial freshen the composition and then we'LL have to go ahead and find a and B. So here, let's write down a V. So it turns out that Bea is one. So we have won over you, minus one and then a cz negative. Once I pull off the minus and then I integrate. So we have a natural log. Absolute value. You might this one. The minus natural are absolute value. You plus our constancy, and then go back to the definition of you the very first part of this problem. But that's how we defied you. So go ahead and replace all the use with X plus one. So here I have X plus one, minus one. So see dick here. Natural log, Absolute value X that minus l end off X plus one. You could put the absolute value here. The reason I dropped was because there are no absolute values. And for this one, this thing, this came from integration by parts. And if this war to make sense, that this term over here was also makes sense. So if we're not going to use absolute value and the first one we mind is what That you set off the second good. So it's going to raise this scratch marks over here, and then that's our final is er.

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Video Thumbnail

01:53

Integration Techniques - Intro

In mathematics, integration is one of the two main operations in calculus, with its inverse, differentiation, being the other. Given a function of a real variable, an antiderivative, integral, or integrand is the function's derivative, with respect to the variable of interest. The integrals of a function are the components of its antiderivative. The definite integral of a function from a to b is the area of the region in the xy-plane that lies between the graph of the function and the x-axis, above the x-axis, or below the x-axis. The indefinite integral of a function is an antiderivative of the function, and can be used to find the original function when given the derivative. The definite integral of a function is a single-valued function on a given interval. It can be computed by evaluating the definite integral of a function at every x in the domain of the function, then adding the results together.

Video Thumbnail

27:53

Basic Techniques

In mathematics, a technique is a method or formula for solving a problem. Techniques are often used in mathematics, physics, economics, and computer science.

Join Course
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