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Numerade Educator



Problem 39 Easy Difficulty

Evaluate the integral.

$ \displaystyle \int \frac{\sec \theta \tan \theta}{\sec^2 \theta - \sec \theta}\ d \theta $


$\ln |1-\cos \theta|+C \quad$ or $\quad \ln |\sec \theta-1|-\ln |\sec \theta|+C$


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Video Transcript

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