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Problem 40 Medium Difficulty

Evaluate the integral.

$ \displaystyle \int^{10}_{-10} \frac{2e^x}{\sinh x + \cosh x} \,dx $


$\int_{-10}^{10} \frac{2 e^{x}}{\sinh x+\cosh x} d x=40$

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Video Transcript

Okay. As you can see, this is our integral. Now, the first thing we know we can do is we know we can simplify this because either the X is sign h of X post coastline h of X, which means we can write this integral as from night of tender 10 to each of the AKs. Divide by each of the AKs. Jax, which just gives us two DX. Now we know the integral to D axes to acts, which means now we can plug in two times 10 is 20 two times negative times negative. 2020 miles. Native 20 is 20 plus 20 which is 40.