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Evaluate the integral.
$ \displaystyle \int^2_{-1} (3u - 2)(u + 1) \,du $
$$\frac{9}{2}$$
01:20
Frank L.
Calculus 1 / AB
Chapter 5
Integrals
Section 3
The Fundamental Theorem of Calculus
Integration
Campbell University
University of Michigan - Ann Arbor
Idaho State University
Boston College
Lectures
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Okay, Integrate. Which means add one to the exponents and then divide by the new exponents. Plug in. We end up with 10 months. One over to which is nine. Divide by two.
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