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# Evaluate the integral.$\displaystyle \int^2_{-1} (3u - 2)(u + 1) \,du$

## $$\frac{9}{2}$$

Integrals

Integration

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### Video Transcript

Okay, Integrate. Which means add one to the exponents and then divide by the new exponents. Plug in. We end up with 10 months. One over to which is nine. Divide by two.

Integrals

Integration

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