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Numerade Educator

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Problem 35 Easy Difficulty

Evaluate the integral.

$ \displaystyle \int^2_1 \frac{v^3 + 3v^6}{v^4} \,dv $

Answer

$$
\ln 2+7
$$

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Video Transcript

integrate, which means increase our exponents by one and divide by the new exponents. So we know the integral of one over V is simply gonna be natural. Log V right? This is a property. So now we can plug in. Natural of one is simply zero giving us not to work with two plus seven.