Download the App!

Get 24/7 study help with the Numerade app for iOS and Android! Enter your email for an invite.

Question

Answered step-by-step

Evaluate the integral.

$ \displaystyle \int^3_1 \frac{y^3 - 2y^2 - y}{y^2} \,dy $

Video Answer

Solved by verified expert

This problem has been solved!

Try Numerade free for 7 days

Like

Report

Official textbook answer

Video by Amrita Bhasin

Numerade Educator

This textbook answer is only visible when subscribed! Please subscribe to view the answer

01:16

Frank Lin

Calculus 1 / AB

Chapter 5

Integrals

Section 3

The Fundamental Theorem of Calculus

Integration

Campbell University

Baylor University

University of Nottingham

Lectures

05:53

In mathematics, an indefinite integral is an integral whose integrand is not known in terms of elementary functions. An indefinite integral is usually encountered when integrating functions that are not elementary functions themselves.

40:35

In mathematics, integration is one of the two main operations of calculus, with its inverse operation, differentiation, being the other. Given a function of a real variable (often called "the integrand"), an antiderivative is a function whose derivative is the given function. The area under a real-valued function of a real variable is the integral of the function, provided it is defined on a closed interval around a given point. It is a basic result of calculus that an antiderivative always exists, and is equal to the original function evaluated at the upper limit of integration.

0:00

Evaluate the integral.…

09:56

00:53

Evaluate the indefinite in…

02:31

Evaluate the given integra…

02:12

02:21

05:51

Evaluate.$$\int_{-a}^{…

evaluate the integrals of …

02:52

Evaluate the following int…

02:11

13:24

Evaluate the integrals…

02:55

Evaluate the integrals.

01:29

Evaluate $\int_{1}^{3} \in…

okay. We know the first thing we can do is divide by the denominator in order to simplify this further before integration. When we end up with dust now we can integrate. Increase the exploited by one divide by the new exponents from the bounds of 123 No, we're plugging in when we get negative. Natural Look of three is our solution.

View More Answers From This Book

Find Another Textbook