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# Evaluate the integral. $\displaystyle \int^3_1 \frac{y^3 - 2y^2 - y}{y^2} \,dy$

## $$-\ln 3$$

Integrals

Integration

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### Video Transcript

okay. We know the first thing we can do is divide by the denominator in order to simplify this further before integration. When we end up with dust now we can integrate. Increase the exploited by one divide by the new exponents from the bounds of 123 No, we're plugging in when we get negative. Natural Look of three is our solution.

Integrals

Integration

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