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Evaluate the integral.
$ \displaystyle \int^5_{-5} e \,dx $
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00:46
Frank Lin
00:17
Amrita Bhasin
Calculus 1 / AB
Chapter 5
Integrals
Section 3
The Fundamental Theorem of Calculus
Integration
Oregon State University
Harvey Mudd College
University of Nottingham
Idaho State University
Lectures
05:53
In mathematics, an indefinite integral is an integral whose integrand is not known in terms of elementary functions. An indefinite integral is usually encountered when integrating functions that are not elementary functions themselves.
40:35
In mathematics, integration is one of the two main operations of calculus, with its inverse operation, differentiation, being the other. Given a function of a real variable (often called "the integrand"), an antiderivative is a function whose derivative is the given function. The area under a real-valued function of a real variable is the integral of the function, provided it is defined on a closed interval around a given point. It is a basic result of calculus that an antiderivative always exists, and is equal to the original function evaluated at the upper limit of integration.
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Okay, now we're going to answer the question. The integral off negative 5 to 5 e d. X Evaluate this thing. Okay, this is actually a trick question. A lot of people will associate E with the exponential function E to the X. Who's derivative is going to be e to the X and the integral is also a family of E to the X. Let's just not forget that are constant also comes into play. However, this is not a net exponential function. It doesn't have any X in the power. This is just eat. So it's almost the same as saying Find the integral off three approximately or 2.718 if you remember what this constant is approximately equal to. So this is simply a polynomial, a constant polynomial. So if you take the anti derivative, it'll be e times x, not eat to the X, okay, and then we can plug in negative 5 to 5. Of course, this is just a rectangle with height e where the base is going to be length 10 because that's a distance from negative 5 to 5. The answer is 10 e. So please do not fall for the job for this problem
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