Problem

Evaluate the integral. $ \displaystyle \int^{\…

00:29

Problem 24 Easy Difficulty

Evaluate the integral.

$ \displaystyle \int^8_1 x^{-2/3} \,dx $

Answer

$$
\int_{1}^{8} x^{-2 / 3} d x=3
$$

More Answers

00:30

Frank L.

Topics

Integrals

Integration

Book Cover for Calculus: Early Tra…

Calculus: Early Transcendentals

Chapter 5

Integrals

Section 3

The Fundamental Theorem of Calculus

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Video Transcript

integrate meaning. Add one to the exponents and divide by the new exponents. We can simplify this to be three x to the 1/3 from the bounds of 1 to 8. This is three times two months, three times one, which is six months three, which is three.

Amrita B.

Topics

Integrals

Integration

Book Cover for Calculus: Early Tra…

Calculus: Early Transcendentals

Chapter 5

Integrals

Section 3

The Fundamental Theorem of Calculus

Top Calculus 1 / AB Educators

Catherine R.

Missouri State University

Heather Z.

Oregon State University

Samuel H.

University of Nottingham

Michael J.

Idaho State University