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Evaluate the integral.

$ \displaystyle \int_0^1 \frac{r^3}{\sqrt{4 + r^2}} dr $

$\int_{0}^{1} \frac{r^{3}}{\sqrt{4+r^{2}}} d r=\frac{16-7 \sqrt{5}}{3}$

Integration Techniques

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Oregon State University

Harvey Mudd College

University of Michigan - Ann Arbor

University of Nottingham

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