Question
Evaluate the integral.$\int_{0}^{2 \pi} \sin ^{2}\left(\frac{1}{3} \theta\right) d \theta$
Step 1
So, we can rewrite the integral as: \[\int_{0}^{2 \pi} \sin ^{2}\left(\frac{1}{3} \theta\right) d \theta = \frac{1}{2} \int_{0}^{2 \pi} (1 - \cos \frac{2\theta}{3}) d \theta\] Show more…
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