Question
Evaluate the integral.$$\int_{0}^{2}\left(x^{4}-\frac{1}{4} x^{2}+\frac{1}{3} x-1\right) d x$$
Step 1
The integral of $x^{4}$ is $\frac{x^{5}}{5}$, the integral of $-\frac{1}{4}x^{2}$ is $-\frac{1}{12}x^{3}$, the integral of $\frac{1}{3}x$ is $\frac{1}{6}x^{2}$, and the integral of $-1$ is $-x$. So, the integral of the function Show more…
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