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# Evaluate the integral.$\int_{0}^{4}(4-t) \sqrt{t} d t$

## $$\int_{0}^{4}(4-t) \sqrt{t} d t=\frac{128}{15}$$

Integrals

Integration

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### Video Transcript

integrate, which means that we increase our exponents by Juan and then divide by the new exponents. So in your expert in this three over to you can see we're dividing by that plug in. This is equivalent to 128. Divide by 15.