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Problem

Evaluate the integral. $$ \int_{1}^{3} \frac{d x}…

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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54

Problem 24 Medium Difficulty

Evaluate the integral.
$$
\int_{\sqrt{2}}^{2} \frac{\sqrt{2 x^{2}-4}}{x} d x
$$

Answer

$2-\frac{\pi}{2}$

Related Courses

Calculus 1 / AB

Calculus 2 / BC

Calculus Early Transcendentals

Chapter 7

PRINCIPLES OF INTEGRAL EVALUATION

Section 4

Trigonometric Substitutions

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Integrals

Integration

Integration Techniques

Trig Integrals

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Problem 7
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Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
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Problem 21
Problem 22
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Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
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Problem 37
Problem 38
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Problem 41
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Problem 46
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Problem 54

Video Transcript

We have given the integral dinero to rotunda 2 spins 4, divided by x into d s. Now substitute here x is equal to root 2 sec theta. When we substitute x equal to root 2 sec theta here, then you can remove the square root from here. So take the derivative both sides, so d x, is equal to root 2. As you know, the derivative of sex theta. We can write x 50 into tan theta into d theta, now substitute the value of x and d x, given integral first here compute. The limit in terms of theta when x is equal to root 2. The value of theta is, we can write when x is also rotolo. Theta is so we can write here 0. When x is equal to 2, then the value of theta is pi by 4, now substitute here so 2 into root, 2 sec fictile whole square. Minus 4 divided by root 2 sec theta and the place of dean, write root 2 sec theta into tan theta into de tita. Now simplify this expression. Then we will get from here, then we'll get from here 2 into 0 to pi by 4 tan theta into tan theta into d theta. Now we can write like that 2 into 025 by 4, here 10 square theta into detent. As you know, the integration of the 10 square theta is equal to sec theta. Sorry. Here we can write in the place of 10 square theta sec square theta, minus 1 point. As you know, 10 square theta is equal to sec square theta minus 1 into the theta now integrate integrate here. The integration of the sac square theta is equal to tan theta, and the integration of the 1 is theta into 2 ketland. The limit to pi by 4 point now plug in the limit here so first we'll plug upper limit, so 210 pi by 4 minus 2 into pi by 4. When you plug here 0, then we'll get all terms are 0 here now the value of 10 pi by 4 is 12 into 1 minus pi by 2. So the answer of this question is 2 minus pi by 2 now simplify more then we can write 4 minus pi by 2. So this is the answer of the given integral. Thank you.

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Howard Anton, Irl Bivens, Stephen Davis

Calculus Early Transcendentals

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