00:01
Here in this problem we are given the integral with the limit 0 to pi by 4.
00:07
8 into cosine q into 2 theta, sine into 2 theta into d theta.
00:16
Here m is even and n is o, so we use the formula.
00:22
Cosine square theta is equals to 1 minus sine square theta.
00:28
So we have 8 into integral with the limit 0 to pi by 4.
00:36
Cosine squared 2 theta into cosine 2 theta into sine 2 theta into d theta it would be equal to 8 into integral with the limit 0 to pi by 4 1 minus sine squared 2 theta into cosine 2 theta into sine 2 theta into d theta let sign 2 theta is equal to t.
01:13
By differentiating with respect to t, we get 2 .0002 theta into d theta is equal to d t.
01:24
If theta is equal to 0, then the lower limit t is equal to 0.
01:30
And if theta is equal to pi by 4, then the upper limit t is equal to sine...