Let's start by rewriting the integral using a trigonometric identity. Recall that \(\tan^2 x = \sec^2 x - 1\). Therefore, the integral becomes:
\[
\int_{0}^{\pi / 3} x \tan^2 x \, dx = \int_{0}^{\pi / 3} x (\sec^2 x - 1) \, dx
\]
This can be split into two
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