00:01
Okay, so let's start by rewriting 9 as 3 to the power of 2.
00:06
And now we see that we can rewrite our x as x is equal to 3 tangents of theta.
00:14
And now dx will be equal to 3 secants, square of beta, d theta.
00:20
Okay, so let's replace our x terms.
00:22
So we get the square root or the integral of 9 tangents squared of data and then dx is three sequence squared of data the data over the square roots of we have nine and nine here so we can factor out a square root of nine which is three and then we have the square root of tangent squared plus one that's equal to sequence squared of data so we can get rid of our square and our roots and now we can cancel one of our sequence and our three and we're left with the integral or nine integral of tangents squared of data, secant, theta, d theta.
01:11
Okay, so we want to take the integral of the following.
01:13
So let's see.
01:16
If we take u to be tangents, we need tiquant squared, but we don't have that...