00:01
Okay, so we should have our square root.
00:02
We have x squared minus 1.
00:04
So this means that x is equal to that's equal to secan of data.
00:11
So then dx, that should be equal to sequence of data, tangent of data, d beta.
00:20
Okay.
00:21
So to rewrite our fallen integral, so x is secant cubed data.
00:27
And then we have the square roots of ccant squared minus 1, that's tangent, squared of data, d theta, or actually d x is sequence of data, tangents of data, d theta.
00:42
Okay, so we actually get secence to the power of four data, and then tangent to the power of two data, d theta.
00:51
Okay, so let's rewrite this, or let's use u sub so we can take u to be equal to tangent of data, then du that's equal to sequence squared of data d theta.
01:10
Okay, so we have remaining sequins squared.
01:12
We can rewrite that in terms of tangents with our pythagorean identity.
01:17
That is rewriting it in terms of tangents.
01:21
That's secant squared minus one.
01:26
Actually, we want to rewrite it in terms of tangent...