We can let \(u = x^3\), which implies that \(du = 3x^2dx\). We can also adjust the limits of integration accordingly. When \(x = 0\), \(u = 0^3 = 0\), and when \(x = 1\), \(u = 1^3 = 1\). So, the limits of integration remain the same, from 0 to 1.
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