Question
Evaluate the integrals.$$\int_{0}^{1}\left(4 x^{3}-3 x^{2}+4 x-1\right) d x$$
Step 1
The power rule states that the integral of x^n dx is (1/(n+1))x^(n+1). Applying this rule to each term in the function, we get: $$ \int (4x^3 - 3x^2 + 4x - 1) dx = 4\int x^3 dx - 3\int x^2 dx + 4\int x dx - \int dx $$ Show more…
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