Question
Evaluate the integrals.$$\int_{1}^{2} \frac{8 d x}{x^{2}-2 x+2}$$
Step 1
Step 1: First, we rewrite the integral as follows: $$\int_{1}^{2} \frac{8 d x}{x^{2}-2 x+2} = \int_{1}^{2} \frac{8 d x}{(x-1)^{2}+1}$$ This is done by completing the square in the denominator. Show more…
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