Question
Evaluate the integrals using Part 1 of the Fundamental Theorem of Calculus.$$\int_{-2}^{1}\left(x^{2}-6 x+12\right) d x$$
Step 1
The antiderivative of $x^{2}$ is $\frac{x^{3}}{3}$, the antiderivative of $-6x$ is $-3x^{2}$, and the antiderivative of $12$ is $12x$. So, the antiderivative of the function is $\frac{x^{3}}{3}-3x^{2}+12x$. Show more…
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