Question
Evaluate the iterated integral by converting to polar coordinates.$$\int_{0}^{2} \int_{0}^{\sqrt{2 x-x^{2}}} x y d y d x$$
Step 1
In polar coordinates, $x = r\cos(\theta)$ and $y = r\sin(\theta)$. Also, $dx\,dy$ becomes $r\,dr\,d\theta$. So, the integral becomes: $$\int_{0}^{2\pi} \int_{0}^{2\cos(\theta)} r^{2}\cos(\theta)\sin(\theta) r\,dr\,d\theta$$ Show more…
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