Question
Evaluate the limit (a) using techniques from Chapters 1 and 3 and (b) using L'Hôpital's Rule.$$\lim _{x \rightarrow 3} \frac{2(x-3)}{x^{2}-9}$$
Step 1
We get $\frac{2(3-3)}{3^{2}-9} = \frac{0}{0}$, which is an indeterminate form. Show more…
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