Question
Evaluate the limit, if it exists.$$\lim _{x \rightarrow 16} \frac{4-\sqrt{x}}{16 x-x^{2}}$$
Step 1
We get $\frac{4-\sqrt{16}}{16*16-16^2}=\frac{4-4}{256-256}=0/0$, which is an indeterminate form. So, we need to do more work to find the limit. Show more…
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