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Evaluate the limit.$$\lim _{x \rightarrow 0} \frac{\sin 5 x \sin 2 x}{\sin 3 x \sin 5 x}$$

$\lim _{x \rightarrow 0} \frac{\sin 5 x \cdot \sin 2 x}{\sin 3 x \cdot \sin 5 x}=\frac{2}{3}$

Calculus 1 / AB

Chapter 2

LIMITS

Section 6

Trigonometric Limits

Limits

Derivatives

Continuous Functions

Missouri State University

Baylor University

University of Nottingham

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canceling the side of five x er. We need to apply here too. So if you multiply the entire limit but two divided by two ex as well as three X divided by three, we can end up with the limit as X approaches. Zero off this sign of two X divided by two ex multiplied by 2/3 multiplied by three x, divided by the sine of three x, so this is equal to one tends to third Time's one, which is equal to 2 30

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