Question
Evaluate the limit, using L'Hopital's Rule if necessary. (In Exercise 18, $n$ is a positive integer.)$$\lim _{x \rightarrow 3} \frac{x^{2}-2 x-3}{x-3}$$
Step 1
We get $\frac{3^{2}-2 \cdot 3-3}{3-3} = \frac{9-6-3}{0} = \frac{0}{0}$. This is an indeterminate form, so we can apply L'Hopital's Rule. Show more…
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